According to Catalan, 2NCN = ∑I NCI 2. Since N C 0 = N C N = 1, there’s where our 2 comes from. It turns out that N C x where 1 < X < N. Therefore N C I = 2 + ∑ 1
One issue with this: I have yet to find a counterexample that isn’t in the form pq where p and q are both prime. Interesting?
Cool problem huh? Anyone want to conjecture on that final form of the answer?